56a^2+23a=63

Solution for 56a^2+23a=63 equation:

56a^2+23a=63

We move all terms to the left:

56a^2+23a-(63)=0

a = 56; b = 23; c = -63;
Δ = b2-4ac
Δ = 232-4·56·(-63)
Δ = 14641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14641}=121$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-121}{2*56}=\frac{-144}{112}
=-1+2/7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+121}{2*56}=\frac{98}{112}
=7/8
$